|  | Simple sscanf parsing problem | | |
| | | Timo |  |
|  Posted: Sat Jun 28, 2008 12:31 pm Post subject: Simple sscanf parsing problem |  |
I haven't been using ANSI-C for string parsing for some time, so even
this simple task is problematic:
I have a string tmp_str, which includes date + time + newline in
format: "25.6.2008 21:49".
I try to parse date from this string to variables tmp1, tmp2, tmp3:
1st attempt:
sscanf(tmp_str, "%d.%d.%d", &tmp1, &tmp2, &tmp3);
All variables get value 0.
2nd attempt
sscanf(tmp_str, "%d %d %d", &tmp1, &tmp2, &tmp3);
tmp3 = 25, others 0.
Any suggestions? |
| |
| | | pete | |
| | Posted: Sat Jun 28, 2008 12:31 pm Post subject: Re: Simple sscanf parsing problem | |
Timo wrote:
| Quote: | I haven't been using ANSI-C for string parsing for some time, so even
this simple task is problematic:
I have a string tmp_str, which includes date + time + newline in
format: "25.6.2008 21:49".
I try to parse date from this string to variables tmp1, tmp2, tmp3:
1st attempt:
sscanf(tmp_str, "%d.%d.%d", &tmp1, &tmp2, &tmp3);
All variables get value 0.
|
I am unable to duplicate your problem.
/* BEGIN new.c output */
25 6 2008
/* END new.c output */
/* BEGIN new.c */
#include <stdio.h>
int main(void)
{
char *tmp_str = "25.6.2008 21:49";
int tmp1, tmp2, tmp3;
sscanf(tmp_str, "%d.%d.%d", &tmp1, &tmp2, &tmp3);
puts("/* BEGIN new.c output */\n");
printf("%d %d %d\n", tmp1, tmp2, tmp3);
puts("\n/* END new.c output */");
return 0;
}
/* END new.c */
--
pete |
| |
| | | CBFalconer | |
| | Posted: Sat Jun 28, 2008 12:31 pm Post subject: Re: Simple sscanf parsing problem | |
Timo wrote:
| Quote: |
I have a string tmp_str, which includes date + time + newline in
format: "25.6.2008 21:49".
I try to parse date from this string to variables tmp1, tmp2, tmp3:
1st attempt:
sscanf(tmp_str, "%d.%d.%d", &tmp1, &tmp2, &tmp3);
All variables get value 0.
2nd attempt
sscanf(tmp_str, "%d %d %d", &tmp1, &tmp2, &tmp3);
tmp3 = 25, others 0.
Any suggestions?
|
Never use a scanf function without checking the error return.
--
[mail]: Chuck F (cbfalconer at maineline dot net)
[page]: <http://cbfalconer.home.att.net>
Try the download section. |
| |
| | | Guest | |
| | Posted: Sat Jun 28, 2008 12:46 pm Post subject: Re: Simple sscanf parsing problem | |
Timo wrote:
Post a compilable complete code that exhibits the behaviour.
The following program outputs "25 6 2008 21 49".
=========================
#include <stdio.h>
int main(void) {
int tmp1, tmp2, tmp3, tmp4, tmp5;
const char date[] = "25.6.2008 21:49";
sscanf(date, "%d.%d.%d %d:%d", &tmp1, &tmp2, &tmp3, &tmp4, &tmp5);
printf("%d %d %d %d %d\n", tmp1, tmp2, tmp3, tmp4, tmp5);
return 0;
} |
| |
| | | Ali Karaali | |
| | Posted: Sat Jun 28, 2008 1:00 pm Post subject: Re: Simple sscanf parsing problem | |
On 28 Haziran, 15:31, Timo <t_i_m_0_n...@yahoo.com> wrote:
| Quote: | I haven't been using ANSI-C for string parsing for some time, so even
this simple task is problematic:
I have a string tmp_str, which includes date + time + newline in
format: "25.6.2008 21:49".
I try to parse date from this string to variables tmp1, tmp2, tmp3:
1st attempt:
sscanf(tmp_str, "%d.%d.%d", &tmp1, &tmp2, &tmp3);
All variables get value 0.
2nd attempt
sscanf(tmp_str, "%d %d %d", &tmp1, &tmp2, &tmp3);
tmp3 = 25, others 0.
Any suggestions?
|
You can use
sscanf (str, "%d%*c%d%*c%d %d%*c%d", &a, &b, &c, &d, &e); |
| |
| | | Timo | |
| | Posted: Sat Jun 28, 2008 1:08 pm Post subject: Re: Simple sscanf parsing problem | |
Thanks for your replies. I found that the reason for this problem was
because of variable types:
unsigned short tmp1;
unsigned char tmp2, tmp3;
They should have been int's, or sscanf format parameters should have
been modified. |
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